Tolong di bantu ya, di buat caranya
[tex]\displaystyle 4\sqrt{3} \times \text{ Sin 60} ^{\circ} - 5 \times \text{ Sin37}^{\circ} = \\\\4\sqrt{3} \times \frac{\sqrt{3}}{2} - 5 \times \frac{3}{5} =\\\\\frac{4\times 3}{2} - 3 = \\\\6-3 = 3[/tex]
Jadi , hasilnya adalah 3
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